-x^2+100x-2275=0

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Solution for -x^2+100x-2275=0 equation:



-x^2+100x-2275=0
We add all the numbers together, and all the variables
-1x^2+100x-2275=0
a = -1; b = 100; c = -2275;
Δ = b2-4ac
Δ = 1002-4·(-1)·(-2275)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-30}{2*-1}=\frac{-130}{-2} =+65 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+30}{2*-1}=\frac{-70}{-2} =+35 $

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